a^2+16=(a-4)(a+4)

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Solution for a^2+16=(a-4)(a+4) equation: 


Simplifying
a2 + 16 = (a + -4)(a + 4)

Reorder the terms:
16 + a2 = (a + -4)(a + 4)

Reorder the terms:
16 + a2 = (-4 + a)(a + 4)

Reorder the terms:
16 + a2 = (-4 + a)(4 + a)

Multiply (-4 + a) * (4 + a)
16 + a2 = (-4(4 + a) + a(4 + a))
16 + a2 = ((4 * -4 + a * -4) + a(4 + a))
16 + a2 = ((-16 + -4a) + a(4 + a))
16 + a2 = (-16 + -4a + (4 * a + a * a))
16 + a2 = (-16 + -4a + (4a + a2))

Combine like terms: -4a + 4a = 0
16 + a2 = (-16 + 0 + a2)
16 + a2 = (-16 + a2)

Add '-1a2' to each side of the equation.
16 + a2 + -1a2 = -16 + a2 + -1a2

Combine like terms: a2 + -1a2 = 0
16 + 0 = -16 + a2 + -1a2
16 = -16 + a2 + -1a2

Combine like terms: a2 + -1a2 = 0
16 = -16 + 0
16 = -16

Solving
16 = -16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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